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[gpio] Skip set_use_interrupt call when using default value (#11612)

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This commit is contained in:
J. Nick Koston
2025-10-29 20:28:38 -05:00
committed by GitHub
parent 08aae39ea4
commit 29ed3c20af
2 changed files with 7 additions and 4 deletions
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7
tests/component_tests/gpio/test_gpio_binary_sensor.py
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@@ -18,7 +18,8 @@ def test_gpio_binary_sensor_basic_setup(
assert "new gpio::GPIOBinarySensor();" in main_cpp
assert "App.register_binary_sensor" in main_cpp
assert "bs_gpio->set_use_interrupt(true);" in main_cpp
# set_use_interrupt(true) should NOT be generated (uses C++ default)
assert "bs_gpio->set_use_interrupt(true);" not in main_cpp
assert "bs_gpio->set_interrupt_type(gpio::INTERRUPT_ANY_EDGE);" in main_cpp
@@ -51,8 +52,8 @@ def test_gpio_binary_sensor_esp8266_other_pins_use_interrupt(
"tests/component_tests/gpio/test_gpio_binary_sensor_esp8266.yaml"
)
# GPIO5 should still use interrupts
assert "bs_gpio5->set_use_interrupt(true);" in main_cpp
# GPIO5 should still use interrupts (default, so no setter call)
assert "bs_gpio5->set_use_interrupt(true);" not in main_cpp
assert "bs_gpio5->set_interrupt_type(gpio::INTERRUPT_ANY_EDGE);" in main_cpp